Nitrogen laser produces a radiation at a wavelength of 337nm. If the number of photons emitted per second is 3.37×1024, calculate the power of this laser.
(Given : h=6.62×10−34 J.s)
A
4.5×106J
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B
1.99×106J
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C
3.3×106J
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D
2.4×106J
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Solution
The correct option is B1.99×106J Given: Wave length(λ)=337nm=337×10−9m Energy of one photon=hcλ Power of laser P=Energy emitted per second=Nhcλ =3.37×1024×6.62×10−34×3×108337×10−9 =1.99×106J