The diagram shows the Maxwell’s speed distribution curves for a certain ideal gas at two different temperature $T_{1}$ and $T_{2}$ . Pick the correct options:
Take $R = \frac{1}{12} L atm/molK$

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Nitrogen (N2) is in equilibrium state at T=421K. The value of most probable speed, vmp is

The correct option is D 500 m/sMolecular mass of nitrogen, M=28×10−3kgTemperature T=421KMost probable speed vmp=√2RTM∴ vmp=√2×8.3×42128×10−3⟹ vmp=500 m/s

Nitrogen $(N_{2})$ is in equilibrium state at $T = 421 K$ . The value of most probable speed, $v_{m p}$ is

The correct option is D 500 m/s
Molecular mass of nitrogen, $M = 28 \times 10^{- 3} k g$
Temperature $T = 421 K$
Most probable speed $v_{m p} = \sqrt{\frac{2 R T}{M}}$
$∴$ $v_{m p} = \sqrt{\frac{2 \times 8.3 \times 421}{28 \times 10^{- 3}}}$
$⟹$ $v_{m p} = 500$ $m / s$