Nitrogen reacts with oxygen to form $N i t r o g e n (I I)$ oxide.
The volume ratio of reactants to products is:

1 : 2 : 2

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1 : 1 : 1

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2 : 1 : 2

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1 : 1 : 2

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Solution

The correct option is D $1 : 1 : 2$
The equation for reaction between nitrogen and oxygen to form nitrogen (ll) oxide is written as: $N_{2} + O_{2} \to 2 N O$
Therefore, the volume ratio of reactants to products is $= 1 : 1 : 2$

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