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Standard VII

Chemistry

Rate of Reaction

Nitrogen tetr...

Question

Nitrogen tetra oxide $(N_{2} O_{4})$ decomposes as $N_{2} O_{4} (g) \to 2 N O_{2} (g)$ . If the pressure of $(N_{2} O_{4})$ falls from 0.50 atm to 0.32 atm is 30 minutes, the rate of appearance of $N O_{2} (g)$ is

0.006 atm/min

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0.003 atm/min

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0.012 atm/min

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0.024 atm/min

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Solution

The correct option is C 0.012 atm/min
Rate of disappearance of $N_{2} O_{4}$
$= \frac{Δ [N_{2} O_{4}]}{Δ t} = \frac{0.50 - 0.32}{30}$
= 0.006 atm/min
Rate of appearance of $N O_{2}$ = Twice of rate of disappearance of $N_{2} O_{4}$
$= 2 \times 0.006$ = 0.012 atm/min

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Similar questions

Q. Nitrogen tetra oxide

(N_{2} O_{4})

decomposes as

N_{2} O_{4} (g) \to 2 N O_{2} (g)

. If the pressure of

(N_{2} O_{4})

falls from 0.50 atm to 0.32 atm is 30 minutes, the rate of appearance of

N O_{2} (g)

Q. 1 mole of

N_{2} O_{4} (g)

at 300K is kept in a closed container under 1 atm pressure. It is heated to 600K when 20

%

by mass of

N_{2} O_{4} (g)

decomposes to

N O_{2} (g)

. The resultant pressure is

Q. One mole of

N_{2} O_{4} (g)

at 300 K is kept in a closed container under 1 atomsphere. It is heated to 600K when 20% by mass of

N_{2} O_{4}

decomposes to

N O_{2} (g)

. The resultant pressure (in atm) is .

Q. When

0.5 m o l

N_{2} O_{4}

is placed in a

4.00 L

reaction vessel and heated at

400 K

79.3

% of the

N_{2} O_{4}

decomposes to

N O_{2}

. Calculate

K_{c}

and

K_{p}

400 K

for the reaction

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

Q. For the decomposition reaction:

N_{2} O_{4 (g)} \to 2 {N O}_{2 (g)}

; the initial pressure of

N_{2} O_{4}

falls from 0.46 atm to 0.28 atm in 30 minute. What is the rate of appearance of

{N O}_{2}

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Nitrogen tetra oxide (N2O4) decomposes as N2O4(g)→2NO2(g). If the pressure of (N2O4) falls from 0.50 atm to 0.32 atm is 30 minutes, the rate of appearance of NO2(g) is

The correct option is C 0.012 atm/min Rate of disappearance of N2O4 =Δ[N2O4]Δt=0.50−0.3230 = 0.006 atm/min Rate of appearance of NO2 = Twice of rate of disappearance of N2O4 =2×0.006 = 0.012 atm/min

Nitrogen tetra oxide $(N_{2} O_{4})$ decomposes as $N_{2} O_{4} (g) \to 2 N O_{2} (g)$ . If the pressure of $(N_{2} O_{4})$ falls from 0.50 atm to 0.32 atm is 30 minutes, the rate of appearance of $N O_{2} (g)$ is

The correct option is C 0.012 atm/min
Rate of disappearance of $N_{2} O_{4}$
$= \frac{Δ [N_{2} O_{4}]}{Δ t} = \frac{0.50 - 0.32}{30}$
= 0.006 atm/min
Rate of appearance of $N O_{2}$ = Twice of rate of disappearance of $N_{2} O_{4}$
$= 2 \times 0.006$ = 0.012 atm/min