$N O_{3}^{-}$ is reduced to $N H_{4}^{+}$ . What is change in oxidation number?

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Solution

The oxidation state of $N$ in $N O_{3}^{-}$ is +5. The oxidation state of $N$ in $N H_{4}^{+}$ ion is -3. Hence, the change in the oxidation number is from +5 to -3 or 8.

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