$N O_{3}^{-}$ solution produce brown ring with $F e S O_{4}$ & dil. $H_{2} S O_{4}$ .

State whether the given statement is true or not

True

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False

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Solution

The correct option is B False
The given statement is false.
When aqueous salt solution is treated with ferrous sulphate (freshly prepared), and conc sulphuric acid is poured in the test tube from sides, a brown ring is formed due to complex formation at the interface between two liquids.
$N a N O_{2} + H_{2} S O_{4} \to N a H S O_{4} + H N O_{3}$
$6 F e S O_{4} + 3 H_{2} S O_{4} + 2 H N O_{3} \to 3 F e_{2} (S O_{4})_{3} + 4 H_{2} O + 2 N O$
$F e S O_{4} + 5 H_{2} O + N O \to [F e (H_{2} O)_{5} N O] S O_{4}$

Suggest Corrections

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N O_{3}^{-}

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X

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_{3}

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