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Question
NO(g)+O3(g)→NO2(g)+O2(g) triangleH=−198.9 kJ/mol
O3(g)→3/2 O2(g) △H=−142.3 kJ/mol
O2(g)→2O(g) △H=+495.0 kJ/mol
The enthalpy change (△H) for the following reaction is
NO(g)+O(g)→NO2(g)
O3(g)→3/2 O2(g) △H=−142.3 kJ/mol
O2(g)→2O(g) △H=+495.0 kJ/mol
The enthalpy change (△H) for the following reaction is
NO(g)+O(g)→NO2(g)
NO(g)+O(g)→NO2(g)
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Solution
The correct option is A −304.1 kJ/mol
NO(g)+O3(g)→NO2(g)+O2(g);ΔH=−198.9kJ/mol−−−−−(i)O3(g)→32O2(g);ΔH=−142.3kJ/mol32O2(g)→O3(g);ΔH=142.3kJ/mol−−−−−(ii)O2(g)→2O(g);ΔH=+495.0kJ/mol2O(g)→O2(g);ΔH=−495.0kJ/molO(g)→12O2(g);ΔH=−495.02kJ/mol−−−−−(iii)Adding(i),(ii)and(iii),NO(g)+O(g)→NO2(g);ΔH=(−198.9+142.3−495.02)kJ/mol∴ΔH=−304.1kJ/mol
NO(g)+O3(g)→NO2(g)+O2(g);ΔH=−198.9kJ/mol−−−−−(i)O3(g)→32O2(g);ΔH=−142.3kJ/mol32O2(g)→O3(g);ΔH=142.3kJ/mol−−−−−(ii)O2(g)→2O(g);ΔH=+495.0kJ/mol2O(g)→O2(g);ΔH=−495.0kJ/molO(g)→12O2(g);ΔH=−495.02kJ/mol−−−−−(iii)Adding(i),(ii)and(iii),NO(g)+O(g)→NO2(g);ΔH=(−198.9+142.3−495.02)kJ/mol∴ΔH=−304.1kJ/mol
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