Question

No. of covalent bond present in the Lewis structure of ${ICl}_4^{-}$ are:

• A. $4$
• B. $3$
• C. $5$
• D. $2$

Answer 1

The correct option is A $4$

$IC{l}_4^{-}$ is $s{p}^3{d}^2$ hybridized.

Since the electronegativity difference between $Cl$ and $I$ is very less, iodine forms $4$ covalent double bonds with $4$ chlorine atoms.

So, the correct answer is $A$