Question

No. of geometrical isomers for the molecules?

• A. 2
• B. 3
• C. 6
• D. 5

Answer 1

The correct option is B 3

Number of sites where geometrical isomers are possible$=n=2$

Molecule is symmetrical, so formula used to calculate number of geometrical isomers is$=2^{n-1}+2^{p-1}$

$p=\frac{n}{2}$ (if $n$ is even)

$p=\frac{n+1}{2}$ (if $n$ is odd)

$\therefore$Total number of geometrical isomers is$=2^{n-1}+2^{p-1}=2^{2-1}+2^{\frac{2}{2}-1}=2^1+2^0=2+1=3$