wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

No. of permutations of 25 dissimilar things taken more than 15 at a time when repetitions are allowed is

A
2524(25252515)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2524(25252510)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2524(2525+2515)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2524(2525+2510)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2524(25252515)
No of permutations of 16 objects =2516
No of permutations of 17 objects =2517
18 2518
19 2519
25 2525
So, S = 2525+2524+................+2516
= 2516[25101]251
Ans = 2524(25252515)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon