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Byju's Answer
Standard XII
Mathematics
Conditions for a system of linear equations to have infinite solutions
No. of Soluti...
Question
No. of Solutions for:
4
3
x
+
2
y
=
8
2
x
+
3
y
=
12
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Solution
By taking LCM and rearranging equation 1, we get
4
x
+
6
y
=
24
(
1
)
taking equation 2 as it is
2
x
+
3
y
=
12
(
2
)
Here we can see that
e
q
(
1
)
=
2
×
e
q
(
2
)
So these 2 lines are coincident and hence infinitely many solutions exist.
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1
Similar questions
Q.
Solve:
1
2
(
2
x
+
3
y
)
+
12
7
(
3
x
−
2
y
)
=
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2
and
7
2
x
+
3
y
+
4
3
x
−
2
y
=
2
, where
2
x
+
3
y
≠
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and
3
x
−
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y
≠
0
.
Q.
If
1
2
(
2
x
+
3
y
)
+
12
7
(
3
x
−
2
y
)
=
1
2
,
7
(
2
x
+
3
y
)
+
4
(
3
x
−
2
y
)
=
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, then the value of
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+
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y
)
is
Q.
Solve
x
+
y
+
2
z
=
4
;
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x
+
2
y
+
4
z
=
8
;
3
x
+
3
y
+
6
z
=
12
by using determinant method.
Q.
The values of
a
and
b
, for which the system of equations
2
x
+
3
y
+
6
z
=
8
x
+
2
y
+
a
z
=
5
3
x
+
5
y
+
9
z
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has no solution, are
Q.
Which of the following pairs of linear equations has unique solution, no solution, or infinitely many solutions.
(i)
x
−
3
y
−
3
=
0
;
3
x
−
9
y
−
2
=
0
(ii)
2
x
+
y
=
5
;
3
x
+
2
y
=
8
(iii)
3
x
−
5
y
=
20
;
6
x
−
10
y
=
40
(iv)
x
−
3
y
−
7
=
0
;
3
x
−
3
y
−
15
=
0
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Standard XII Mathematics
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