No. of wave in third Bohr's orbit of hydrogen is ________.

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Solution

Number of waves $= \frac{C i r c u m f e r e n c e}{W a v e l e n g t h}$

$\frac{2 π r}{λ} = \frac{2 π r}{h / m v} = \times \frac{2 π}{h} m v r = \frac{2 π}{h} \times \frac{n h}{2 π}$

$∴ n = 3$

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