No. of ways of selecting 2 girls and 3 boys from 3 girls and 5 boys is

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Solution

The correct option is B 30
2 girls from 3 can be selected in $^{3} C_{2}$ ways
And 3 boys from 5 can be selected in $^{5} C_{3}$ ways
Hence by multiplication principle,
The required number of ways $=^{3} C_{2} \times^{5} C_{3} = 3 \times 10 = 30$

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