No perfect cube can end with exactly:

two zeros

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three zeros

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no zeros

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7

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Solution

The correct option is A two zeros
A perfect cube of a number is obtained by multiplying the number by itself three times.
Eg: $1^{3} = 1 \times 1 \times 1 = 1$
$2^{3} = 2 \times 2 \times 2 = 8$
$3^{3} = 3 \times 3 \times 3 = 27$ .
Similarly, $10^{3} = 10 \times 10 \times 10 = 1000$ .

So, perfect cubes can never end with one or two zeroes and have to end with exactly $3$ zeroes or number of zeros equal to the multiple of $3$ .

Hence, option $A$ is correct.

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Similar questions

Q. A perfect cube does not end with two zeros

State true or false:

A perfect cube may end with two zeros.

Write true (T)I or false (f) for the followiong statements:
(i) 392 is a perfect cube.
(ii) 8640 is not a perfect cube.
(iii) No cube can end with exactly two zeros.
(iv) There is no perfect cube which ends in 4.
(v) For an integer $a, a^{3}$ is always greater than $a^{2}$
(vi) if a and b are integers such that $a^{2} > b^{2}, t h e n a^{3} > b^{3}$
(vii) If a adivides b, then $a^{3}$ divides $b^{3}$
(viii) If $a^{2}$ ends in 9 then $a^{3}$ ends in 7.
(ix) If $a^{2}$ ends in 5, then $a^{3}$ ends in 25.
(x) If $a^{2}$ ends in an even number of zeros. than $a^{3}$ ends in an odd number of zeros.

Question 2(ii)

State True or False.
A perfect cube does not end with two zeroes.

Can a perfect cube end with 1 zero?

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