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Mole Concept

NO reacts wit...

Question

$N O$ reacts with $O_{2}$ to form $N O_{2}$ . When 100 g of $N O_{2}$ is formed during reaction the mass of $O_{2}$ consumed is:

3.47 g

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34.78 g

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50 g

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none of these

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Solution

The correct option is B 34.78 g
$2 N O + O_{2} ⟶ 2 N O_{2}$ $O_{2} = 32 g; N O = 30 g; N O_{2} = 46 g$
$2$ moles $1$ mole $2$ moles
$60 g$ $32 g$ $92 g$
$100 g$ of $N O_{2} = \frac{100}{46} = 2.17$ moles
Mass of $O_{2}$ consumed= $\frac{100 \times 32}{92} = 34.78 g$

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Similar questions

N O

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N O_{2}

when

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N O_{2}

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NO reacts with O2 to form NO2. When 100 g of NO2 is formed during reaction the mass of O2 consumed is:

The correct option is B 34.78 g2NO+O2⟶2NO2 O2=32g;NO=30g;NO2=46g2 moles 1 mole 2 moles 60g 32g 92g100g of NO2=10046=2.17 molesMass of O2 consumed= 100×3292=34.78g

$N O$ reacts with $O_{2}$ to form $N O_{2}$ . When 100 g of $N O_{2}$ is formed during reaction the mass of $O_{2}$ consumed is:

The correct option is B 34.78 g
$2 N O + O_{2} ⟶ 2 N O_{2}$ $O_{2} = 32 g; N O = 30 g; N O_{2} = 46 g$
$2$ moles $1$ mole $2$ moles
$60 g$ $32 g$ $92 g$
$100 g$ of $N O_{2} = \frac{100}{46} = 2.17$ moles
Mass of $O_{2}$ consumed= $\frac{100 \times 32}{92} = 34.78 g$