No teacher from the Commerce stream is to be included?

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Solution

The correct option is D 84
When no teacher from the Commerce stream is to be included, then number of ways
$=^{9} C_{6} = \frac{9!}{(9 - 6)! \times 6!} = \frac{9 \times 8 \times 7 \times 6!}{3 \times 2 \times 6!} = 3 \times 4 \times 7 = 84$

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Similar questions

Q. Two teachers from each stream are to be included?

Q. There are 6 teachers of whom two are from Science, 2 from Arts and the remaining, two from Commerce. They have to stand in a line so that the 1 two Science teachers, two arts teachers and also the two Commerce teachers are together. Find the number of ways in which they can do so:

In 2007, out of a total of 2000 applicants in a college, 200 were from commerce background. The no of girls was 750, out of which 330 were from science stream. In 2008, the total no of applicants was 3500 of which 2200 were boys. The no of students from science stream was 1100 of which 610 were girls. Tabulate the given information.

Q. Commerce includes activities relating to trade and ___________ to trade.

Q. Tabulate the given information.
• In 2016, out of a total of 1250 applicants in a college , 775 were from commerce background. The number of girls was 125, out of which 70 were from science stream.

• In 2017, the total number of applicants for commerce stream was 1390 of which 825 were boys. The number of students from science stream was 270, among which 110 were girls.

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No teacher from the Commerce stream is to be included?

The correct option is D 84When no teacher from the Commerce stream is to be included, then number of ways =9C6=9!(9−6)!×6!=9×8×7×6!3×2×6!=3×4×7=84

The correct option is D 84
When no teacher from the Commerce stream is to be included, then number of ways
$=^{9} C_{6} = \frac{9!}{(9 - 6)! \times 6!} = \frac{9 \times 8 \times 7 \times 6!}{3 \times 2 \times 6!} = 3 \times 4 \times 7 = 84$