No teacher from the Commerce stream is to be included?

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Solution

The correct option is D 84
When no teacher from the Commerce stream is to be included, then number of ways
$=^{9} C_{6} = \frac{9!}{(9 - 6)! \times 6!} = \frac{9 \times 8 \times 7 \times 6!}{3 \times 2 \times 6!} = 3 \times 4 \times 7 = 84$

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Similar questions

Q. Two teachers from each stream are to be included?

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In 2007, out of a total of 2000 applicants in a college, 200 were from commerce background. The no of girls was 750, out of which 330 were from science stream. In 2008, the total no of applicants was 3500 of which 2200 were boys. The no of students from science stream was 1100 of which 610 were girls. Tabulate the given information.

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No teacher from the Commerce stream is to be included?

The correct option is D 84When no teacher from the Commerce stream is to be included, then number of ways =9C6=9!(9−6)!×6!=9×8×7×6!3×2×6!=3×4×7=84

The correct option is D 84
When no teacher from the Commerce stream is to be included, then number of ways
$=^{9} C_{6} = \frac{9!}{(9 - 6)! \times 6!} = \frac{9 \times 8 \times 7 \times 6!}{3 \times 2 \times 6!} = 3 \times 4 \times 7 = 84$