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Standard VI

Mathematics

Problems in Everyday Life

NoLi m1 is ...

Question

NoLi $m_{1}$ is displaced by $x_{1}$ while $m_{2}$ is displaced by $x_{2}$ along line joing them. then centre of mass remains at P. Find $\frac{x_{1}}{x_{2}}$

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Solution

$\begin{matrix} m_{1} x_{1} = m_{2} x_{2} \Rightarrow \frac{x_{1}}{x_{2}} = \frac{m_{2}}{m_{1}} ∴ \frac{x_{1}}{x_{2}} = \frac{m_{2}}{m_{1}} - - - - (1) \end{matrix}$

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NoLi m1 is displaced by x1 while m2 is displaced by x2 along line joing them. then centre of mass remains at P. Find x1x2

m1x1=m2x2⇒x1x2=m2m1∴x1x2=m2m1−−−−(1)

NoLi $m_{1}$ is displaced by $x_{1}$ while $m_{2}$ is displaced by $x_{2}$ along line joing them. then centre of mass remains at P. Find $\frac{x_{1}}{x_{2}}$

$\begin{matrix} m_{1} x_{1} = m_{2} x_{2} \Rightarrow \frac{x_{1}}{x_{2}} = \frac{m_{2}}{m_{1}} ∴ \frac{x_{1}}{x_{2}} = \frac{m_{2}}{m_{1}} - - - - (1) \end{matrix}$