Non-stoichiometric cuprous oxide, ${C u}_{2} O$ can be prepared in the labarotory. In this oxide, copper to oxygen ratio is slightly less than $2 : 1$ . Can you account for the fact that this substance is a $p - t y p e$ semiconductor?

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Solution

Since,

It is given that the ratio of $C u^{+}$ ions is lesser as compared to the ratio of Oxide ions,

That means, certain sites where actually there should be the presence of copper ions

(i.e, positive ions) are now vacant.

Thus,

One can say that it has a larger whole concentration than electron concentration.

The phrase $p - t y p e$ refers to the positive charge of the hole.

In $p - t y p e$ semiconductors,

Holes are the majority carriers and electrons are the minority carriers.

Thus, $C u_{2} O$ can act as a $p - t y p e$ semiconductor.

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Non-stoichiometric cuprous oxide, Cu2O can be prepared in the labarotory. In this oxide, copper to oxygen ratio is slightly less than 2:1. Can you account for the fact that this substance is a p−type semiconductor?

Non-stoichiometric cuprous oxide, ${C u}_{2} O$ can be prepared in the labarotory. In this oxide, copper to oxygen ratio is slightly less than $2 : 1$ . Can you account for the fact that this substance is a $p - t y p e$ semiconductor?