Non stoichiometric cuprous oxide, $C u_{2} O$ can be prepared in the laboratory. In this oxide, copper to oxygen ratio is slightly less than 2:1, can you account for the fact that this substance is a p - type semiconductor?

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Solution

The ratio less than 2:1 in $C u_{2} O$ shows that some cuprous $(C u^{+})$ ions have been replaced by cupric $(C u^{+ 2})$ ions. To maintain electrical neutrality, every two $C u^{+}$ ions will be replaced by one $C u^{+ 2}$ ion. Thereby creating a hole. As conduction will be due to the presence of these positive holes, hence it is a p -type semi conductor.

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Non stoichiometric cuprous oxide, Cu2O can be prepared in the laboratory. In this oxide, copper to oxygen ratio is slightly less than 2:1, can you account for the fact that this substance is a p - type semiconductor?

Non stoichiometric cuprous oxide, $C u_{2} O$ can be prepared in the laboratory. In this oxide, copper to oxygen ratio is slightly less than 2:1, can you account for the fact that this substance is a p - type semiconductor?