Question

Nora walked $\frac{88}{179}$ of distance from home to school on foot and $\frac{69}{179}$ of the distance on bicycle and remaining part by car. How much part of distance did she cover by car?

• A. $\frac{22}{179}$
• B. $\frac{157}{179}$
• C. $\frac{23}{179}$

Answer 1

The correct option is A $\frac{22}{179}$

Part of distance, she walked on foot $=\frac{88}{179}$

Part of distance, she travelled on bicycle $=\frac{69}{179}$

Part of distance covered on foot and by car = Part of distance covered on foot + Part of distance covered by car
$=\frac{88}{179}+\frac{69}{179}=\frac{88+69}{179}=\frac{157}{179}$

Part of distance covered by car = Total part of the distance - Distance covered on foot and on bicycle
$=1-\frac{157}{179}=\frac{179}{179}-\frac{157}{179}=\frac{22}{179}$

Hence, she need to cover $\frac{22}{179}$ part of the distance by car.