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Hydrology & Irrigation

Simple Mean Method

Normal annual...

Question

Normal annual rainfall at three stations A, B and C are 168.3, 180.7 and 165.1 cm respectively. It is found that in the year 2000 stations B was inoperative. If the observed precipitations at stations A and C were 160.0 cm and 155.0 cm, the rainfall at station B in that year could be

A

157.5 cm

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B

160.5 cm

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C

172.0 cm

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D

181.5 cm

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Solution

The correct option is A 157.5 cm
$[0.9 \times N_{x}, 1.1 \times N_{x} = [0.9 \times N_{B}, 1.1 \times N_{B}]$

$= [162.63, 198.77]$

$Where 0.9 N_{x} : 10 % lesser value$

$1.1 N_{x} : 10 % higher value$

All other normal rainfall values lies within the range. So by using simple mean method,

$P at B = \frac{160.0 + 155.0}{2} = 157.5 c m$

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