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Standard XII

Chemistry

Elevation in Boiling Point

Normal boilin...

Question

Normal boiling point of water is 373 K (at 760mm). Vapour pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mole, the boiling point of water at 23 mm pressure will be

250 K

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294 K

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51.6 K

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12.5 K

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Solution

The correct option is B
294 K

Applying clausius clapeytron equation

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Similar questions

Normal boiling point of water is 373 K (at 760mm). Vapour pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mole, the boiling point of water at 23 mm pressure will be

Q. The normal boiling of water is

373 K

. Vapour pressure of water at temperature

T

is 19 mm

H g

. If enthalpy of evaporation is

40.67 k J / m o l

, then temperature

T

would be:

(Use

l o g 2 = 0.3, R = 8.3 {J K}^{- 1}

)

Q. The normal boiling of water is 373 K (at 760 mm). Vapour pressure of water at 298 K is 23 mm. If enthalpy of vaporization is

40.656 {k J m o l}^{- 1}

, the boiling point of water at 23 mm atmospheric pressure will be:

Q. Assertion :The normal boiling point of water is

100^{\circ} C

and standard boiling point of water is

{99.6}^{\circ} C

. Reason: The temperature at which vapour pressure of liquid is equal to the external pressure is called boiling temperature at that pressure.

Q. The normal boiling point of water is

373 K

. Vapour pressure of water at temperature

T

19 mm Hg

. If enthalpy of vaporisation is

40671.40 J/mol

, then temperature

T

would be:
(Use :

log 2 = 0.3, R : 8.3 {JK}^{- 1} {mo1}^{- 1}

)

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Normal boiling point of water is 373 K (at 760mm). Vapour pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mole, the boiling point of water at 23 mm pressure will be

The correct option is B 294 KApplying clausius clapeytron equation

The correct option is B
294 K

Applying clausius clapeytron equation