Normality of 2M sulphuric acid is:

2 N

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N/2

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N/4

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Solution

The correct option is D 4N
Equivalent weight [E] of sulphuric acid = Molecular weight of sulphuric acid

$= \frac{M}{(1 \times 2)} = \frac{M}{2}$

So, M = 2E

2M sulphuric acid means ,

1L solution contains 2M sulphuric acid

$= 2 \times 2 E$ Sulphuric acid

= 4E Sulphuric acid = 4N Sulphuric acid

Hence, the correct option is $B$

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