Normally, copper is less reactive metal and can not liberate $H_{2}$ gas with acids. But, when a copper piece is dipped in concentrated $H_{2} S O_{4}$ , copper piece is found to disintegrate after a period of time. Give reason behind it.

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Solution

When a copper piece is dipped in concentrated $H_{2} {S O}_{4}$ , copper piece is found to disintegrate after a period of time because $H_{2} {S O}_{4}$ is an oxidizing agent and it oxidizes copper via following reaction.
$C u + H_{2} {S O}_{4} ⟶ C u {S O}_{4} + H_{2}$

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Similar questions

Q. Iron can liberate

H_{2}

from dil.

H_{2} {S O}_{4}

but copper cannot liberate

H_{2}

from dil.

H_{2} {S O}_{4}

.
Why?

Q. Assertion :Zinc reacts with

H_{2} S O_{4}

to give

H_{2}

gas but copper does not. Reason: Zinc has higher reduction potential than copper.

(a) A dilute acid B does not normally give hydrogen when reacted with metals but does give a gas when reacts with copper. Identify B. Write equation with copper.

(b) Complete the table :

$\begin{matrix} Name of Process & Inputs & Equation & Output Ammonia & Nitric acid +Air \end{matrix}$

Q. Identify the substances B. If dilute acid 'B' which does not normally give hydrogen when reacted with metals but does give a gas when it reacts with copper.

Q. Iron can liberate

H_{2}

from dil.

H_{2} S O_{4}

but copper cannot liberate

H_{2}

from dil.

H_{2} S O_{4}

because :

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Normally, copper is less reactive metal and can not liberate H2 gas with acids. But, when a copper piece is dipped in concentrated H2SO4, copper piece is found to disintegrate after a period of time. Give reason behind it.

When a copper piece is dipped in concentrated H2SO4, copper piece is found to disintegrate after a period of time because H2SO4 is an oxidizing agent and it oxidizes copper via following reaction.Cu+H2SO4⟶CuSO4+H2

Normally, copper is less reactive metal and can not liberate $H_{2}$ gas with acids. But, when a copper piece is dipped in concentrated $H_{2} S O_{4}$ , copper piece is found to disintegrate after a period of time. Give reason behind it.

When a copper piece is dipped in concentrated $H_{2} {S O}_{4}$ , copper piece is found to disintegrate after a period of time because $H_{2} {S O}_{4}$ is an oxidizing agent and it oxidizes copper via following reaction.
$C u + H_{2} {S O}_{4} ⟶ C u {S O}_{4} + H_{2}$