Normals at three points P, Q, R to the parabola y2=4ax meet at the point A and S be its focus, if |SP|.|SQ|.|SR|=λ(SA)2 then, λ = ?
A
a3
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B
a2
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C
a
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D
1
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Solution
The correct option is A a Normal : xt+y=at3+2at (a >0) |PS| . |QS| . |RS| =a3(t21+1)(t22+1)(t23+1) =a3[1+(t21+t22+t23)+{(t1t2)2+(t2t3)2+(t3t1)2}+(t1t2t3)2] =a[a2+2ah−4a2+4a2+h2−4ah+k2] =a[(h−a)2+k2] =a(AS)2