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Question

Note the differences between Muniya and Rani's puppy:
Positions Muniya (age) Puppy (age)
Started walking
Ate food for the first time
Got the first tooth

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Solution

Muniya was born on 5 March 2005.
Muniya started walking on 2 February 2006.
Let's calculate her age from 5 March 2005 to 2 February 2006.
Number of days in March 2005 = 31 − 4 = 27
Number of months from April 2005 to January 2006 = 10
Number of days in February 2006 = 2
So, she was 10 months 29 days old when she started walking.

Now, let's calculate Muniya's age when she ate food for the first time.
She ate for the first time on 5 September 2005.
So, her age will be calculated from 5 March 2005 to 5 September 2006.
Time from 5 March 2005 to 4 September 2005 plus 1 day = 6 months 1 day
So, she was 6 months 1 day old when she started eating for the first time.

Last, we need to find her age when she got her first tooth.
She got her first tooth on 15 September.
Her age at that time = 5 March 2005 to 4 September 2005 + 11 days of September
= 6 months 11 days
Muniya was 6 months 11 days old when she got her first tooth.
Positions Muniya (age) Puppy (age)
Started walking 10 months 29 days After 4 weeks (1 month)
Ate food for the first time 6 months 1 day After 3 weeks
Got the first tooth 6 months 11 days After 3 weeks
Difference between their ages when both started walking = Muniya's age − Puppy's age
= 10 months 29 days − 1 month
= 9 months 29 days


Difference between their ages when both ate food for the first time = Muniya's age − Puppy's age
= 6 months 1 day − 3 weeks
= 5 months 4 weeks 1 day − 3 weeks
= 5 months 1 week 1 day

Difference between their ages when both got their first tooth = Muniya's age − Puppy's age
= 6 months 11 days − 3 weeks
= 5 months 4 weeks 11 days − 3 weeks
= 5 months 1 week 11 days

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