1
Question
Now can you reduce each of these products to a single power?
(i) 52 × 52 × 56
(ii) 74 × 79 × 72
(iii) 42 × 42 × 42
(iv) 35 × 35 × 35 × 35
Now can you reduce each of these products to a single power?
(i) 52 × 52 × 56
(ii) 74 × 79 × 72
(iii) 42 × 42 × 42
(iv) 35 × 35 × 35 × 35
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Solution
(i) 52× 52× 56
= 5(2 + 2) × 56 {xm× xn = x(m + n)}
= 54× 56
= 5(4 + 6)
= 510
(ii) 74× 79× 72
= 7(4 + 9) × 72 {xm× xn = x(m + n)}
= 713× 72
= 7(13 + 2)
= 715
(iii) 42× 42× 42
= 4(2 + 2) × 42 {xm× xn = x(m + n)}
= 44× 42
= 4(4 + 2)
= 46
(iv) 35× 35× 35 × 35
= 3(5 + 5) × 35 × 35 {xm× xn = x(m + n)}
= 310× 35 × 35
= 3(10 + 5) × 35
= 315 × 35
= 3(15 + 5)
= 320
(i) 52× 52× 56
= 5(2 + 2) × 56 {xm× xn = x(m + n)}
= 54× 56
= 5(4 + 6)
= 510
(ii) 74× 79× 72
= 7(4 + 9) × 72 {xm× xn = x(m + n)}
= 713× 72
= 7(13 + 2)
= 715
(iii) 42× 42× 42
= 4(2 + 2) × 42 {xm× xn = x(m + n)}
= 44× 42
= 4(4 + 2)
= 46
(iv) 35× 35× 35 × 35
= 3(5 + 5) × 35 × 35 {xm× xn = x(m + n)}
= 310× 35 × 35
= 3(10 + 5) × 35
= 315 × 35
= 3(15 + 5)
= 320
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