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Question

Now can’t you easily do these?

(i) 4 − (−1)

(ii) 6 − (−2)

(iii) 12 − (−8)

(iv) 2 − (−2)

(v)

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Solution

We know that for any two positive numbers x and y, we have x (y) = x + y.

(i) 4 (1) = 4 + 1 = 5

(ii) 6 (2) = 6 + 2 = 8

(iii) 12 (8) = 12 + 8 = 20

(iv) 2 (2) = 2 + 2 = 4

(v) = =


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