Question

Now compute the powers below:

(i) 2⁴

(ii) 4²

(iii) 2⁵

(iv) 5²

(v) 3⁷

(vi) 10⁷

(vii) 1¹⁰

(viii) 0¹⁰⁰

Answer 1

(i) 2⁴ = (2 × 2) × (2 × 2)

= 4 × 4

= 16

(ii) 4² = 4 × 4

= 16

(iii) 2⁵ = (2 × 2) × (2 × 2 × 2)

= 4 × 8

= 32

(iv) 5² = 5 × 5

= 25

(v) 3⁷ = (3 × 3 × 3) × (3 × 3 × 3 × 3)

= 27 × 81

= 2187

(vi) 10⁷ = (10 × 10 × 10) × (10 × 10 × 10 × 10)

= 1000 × 10000

= 10000000

(vii) 1¹⁰ = (1 × 1 × 1 × 1 × 1) × (1 × 1 × 1 × 1 × 1)

= 1 × 1

= 1

(viii) 0¹⁰⁰ = 0 × 0 × 0 × 0 … 100 times

We know that 0 multiplied with 0 is always 0.

Thus, 0¹⁰⁰ = 0