Now, let, the degree of unsaturation of B = x
The degree of unsaturation of C = y
Total number of stereoisomers of B = z
Total number of stereoisomers of C = m
Then, calculate the value of (xy+1)m+z
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Solution
(9BBN = 9- Borabicyclo [3.3.1] nonane.)
There are no stereoisomers in B and 2 stereoisomers in case of C due to one stereo centre.
So, x=2,y=2,z=0,m=2
So, xy+1(m+z)=52=2.5