Now the force exerted by the liquid on the plate is:
There will be backward viscous force acting on both the sides, first from liquid above the plate, and second from liquid below the plate. In this case dx for one side liquid is 2 cm and for another side liquid, dx is 4cm. so we have Fv=(μAdvdx)1+(μAdvdx)2⇒Fv=0.8×0.01×10.02+0.8×0.01×10.04=0.6N