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nt20 ml of 0....

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nt20 ml of 0.1 M solution of compound Na2CO3.NaHCO3.2H2O is titrated against 0.05M HCl, x mL of HCl is used when phenolphtalein is used as an indicator and y mL of HCl is used when methyl orange is the indicator in two separtate titrations. What is the value of (y-x)?n

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20 mL

0.1 M

solution of compound

N a_{2} C O_{3} \cdot N a H C O_{3} \cdot 2 H_{2} O

is titrated against

0.05 M H C l

x mL

H C l

is used when phenolphthalein is used as an indicator and

y mL

H C l

is used when methyl orange is the indicator in two separate titrations. Hence

(y - x)

20

0.1 M

solution of compound

N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O

is titrated against

0.05 M H C l, x m L

H C l

is used when phenolphthalein is used as an indicator and

y m L

H C l

is used when methyl orange is the indicator in two separate titrations. Hence

(y - x)

40

0.05 M

solution of sesqui-carbonate

(N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O)

is titrated against

0.05 M

H C l

x

H C l

is used when phenolphthalein is the indicator and

y

H C l

is used when methyl orange is the indicator in two separate titrations. Hence,

(y - x)

40 m L

0.05 M N a_{2} C O_{3} \cdot N a H C O_{3} \cdot 2 H_{2} O

(sesquicarbonate) is titrated against

0.05 M H C l . x m L

H C l

is used when phenolphthalein is the indicator and

y m L H C l

is used when methyl orange is the indicator in two separate titrations, hence

(y - x)

Q. Given two mixtures: (A)

N a O H

N a_{2} C O_{3}

(B)

N a H C O_{3}

N a_{2} C O_{3}

.

100

mL of mixture (A) required

a

b

1 M

H C l

in separate titration using phenolphthalein and methyl orange indicators respectively while

100

mL of mixture (B) required

x

y

H C l

solution is separate titration using the same indicators.

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