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Question

ntA lens having focal length f and aperture of diameter d forms an image of intensity I. Aperture of diameter d/2 in central region of lens is covered by a black paper. Focal length of lens and intensity of image now will be respectively-n ntn nta) f/2 and I/2n ntb) f and I/4n ntc) 3f/4 and I/2n ntd) f and 3I/4n ntPl. tell correct option and whyn ntn

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Solution

99996120027-0-0

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