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Standard VIII
Physics
Surface Tension
ntCalculate t...
Question
ntCalculate the Ksp of sparingly soluble salt XY2(s) at 25 degree celcius, if the vapour pressure of its saturated solution in water is 31.78 mm of Hg and vapour pressure of pure water is 31.82 mm of Hg?n
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Q.
Vapour pressure of a saturated solution of a sparingly soluble salt,
A
2
B
2
, is
31.8
mm of Hg at
40
o
C. If vapour pressure of pure water is
31.9
mm of Hg at
40
o
C. Calculate
K
s
p
of
A
2
B
2
at
40
o
C.
Q.
The
K
s
p
(
25
o
C
)
of sparingly salt
X
Y
2
(
s
)
is
3.56
×
10
−
5
(
m
o
l
L
−
1
)
3
and at
30
o
C
,the vapour pressure of its saturated solution in water is 31.78 mm of Hg.Calculate the enthalpy change of the reaction.
( write your answer to nearest integer)
X
Y
2
(
s
)
⇌
X
2
+
(
a
q
)
+
2
Y
⊖
(
a
q
)
Given : Vapour pressure of pure water =31.82 mm of Hg
Q.
The
K
s
p
(
25
o
C
)
of sparingly soluble salt
X
Y
2
is
3.56
×
10
−
5
m
o
l
3
L
−
3
and
30
o
C
, the vapour pressure of its saturated solution in water in 31.78 mm of Hg.
X
Y
2
+
A
q
.
⇌
X
2
+
(
a
q
.
)
+
2
Y
−
(
a
q
.
)
(100% ionisation)
The enthalpy change of the reaction if the vapour pressure of
H
2
O
at
30
o
C
is
31.82
mm in kJ (divide by 25 and write answer to the nearest integer) is_____________.
Q.
The vapour pressure of a saturated solution of sparingly soluble salt
(
X
C
l
3
)
was 17.20 mm Hg at
27
0
C
.If the vapour pressure of pure
H
2
O
is 17.25 mm Hg at 300 k, what is the solubility of sparingly soluble salt
X
C
l
3
in mole/Litre?
Q.
A saturated solution of
X
C
l
3
has a vapour pressure
17.20
mm Hg at
20
∘
C
, while pure water vapour pressure is
17.25
mm Hg. Solubility product
(
K
s
p
)
of
X
C
l
3
at
20
∘
C
is
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