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ntCalculate the Ksp of sparingly soluble salt XY2(s) at 25 degree celcius, if the vapour pressure of its saturated solution in water is 31.78 mm of Hg and vapour pressure of pure water is 31.82 mm of Hg?n

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Q. Vapour pressure of a saturated solution of a sparingly soluble salt,

A_{2} B_{2}

31.8

40^{o}

C. If vapour pressure of pure water is

31.9

40^{o}

K_{s p}

A_{2} B_{2}

40^{o}

K_{s p} (25^{o} C)

of sparingly salt

X Y_{2} (s)

3.56 \times 10^{- 5} {(m o l L^{- 1})}^{3}

30^{o} C

,the vapour pressure of its saturated solution in water is 31.78 mm of Hg.Calculate the enthalpy change of the reaction.( write your answer to nearest integer)

X Y_{2} (s) ⇌ X^{2 +} (a q) + 2 Y^{⊖} (a q)

Given : Vapour pressure of pure water =31.82 mm of Hg

K_{s p} (25^{o} C)

of sparingly soluble salt

X Y_{2}

3.56 \times 10^{- 5} m o l^{3} L^{- 3}

30^{o} C

, the vapour pressure of its saturated solution in water in 31.78 mm of Hg.

X Y_{2} + A q . ⇌ X^{2 +} (a q .) + 2 Y^{-} (a q .)

(100% ionisation)
The enthalpy change of the reaction if the vapour pressure of

H_{2} O

30^{o} C

31.82

mm in kJ (divide by 25 and write answer to the nearest integer) is_____________.

Q. The vapour pressure of a saturated solution of sparingly soluble salt

(X C l_{3})

was 17.20 mm Hg at

27^{0} C

.If the vapour pressure of pure

H_{2} O

is 17.25 mm Hg at 300 k, what is the solubility of sparingly soluble salt

X C l_{3}

Q. A saturated solution of

X C l_{3}

has a vapour pressure

17.20

20^{\circ} C

, while pure water vapour pressure is

17.25

mm Hg. Solubility product

(K_{s p})

X C l_{3}

20^{\circ} C

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