ntCalculate the percentage ionization of 0.01M acetic acid in 0.1M HCL Ka of acetic acid is 1.8 10-5(10 to the power 5)n

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Calculate the percentage ionization of 0.01 M acetic acid in 0.1 M HCl. $K_{a}$ of acetic acid is $1.8 \times 10^{- 5}$ :

[H^{+}]

0.01

(K_{a} = 1.8 \times 10^{- 5})

0.01

(K_{a} = 6.3 \times 10^{- 5})

5.0 m L

0.1 M N a O H

50 m L

0.1 M

p H

(K a = 1.8 \times 10^{- 5})

0.4 M

(K_{a} = 1.8 \times 10^{- 5})

H^{+}

(C H_{3} C O O H)

H C l

K_{a} = 1.8 \times 10^{- 5}

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