MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Other Eyes Defects

ntIn a fresne...

Question

ntIn a fresnel biprism experiment,the two positions of lens give seperation between the slits as 16 cm and 9 cm respectively. What is the actual distance of seperation?n nt13 cmn nt14 cmn nt12.5 cmn nt12 cmn

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

Q. In a Fresnel biprism experiment, the two positions of lens give separation between the slits as

16

9

cm, respectively. What is the actual distance of separation?

Q. In a Fresnel biprism experiment, the two position of lens give separation between the slits as

16 c m

9 c m

, respectively. What is the actual distance of separation?

Q. Find the actual distance between two places if on the map they are seperated by 5 cm. Scale is 1 cm = 2 km.

Q. In a biprism experiment the distance between the two virtual images of the slit is

0.1

cm and the distance between the slit and screen is

1

m. If the band width is

0.058

cm. Calculate the wavelength of light.

Q. In biprism experiment the fringes are observed in the focal plane of the eyepiece at a distance of 1.2 m from slit. The distance between the central bright band and the

20^{t h}

bright band is 0.4 cm. When convex lens is interposed between the biprism and eyepiece, at a distance of 90 cm from the eyepiece, the distance between two magnified virtual images is found to be 0.9 cm. Find the wavelength of light used.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Eye Defects and Its Corrections

PHYSICS

Watch in App

explore_more_icon

Explore more

Other Eyes Defects

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon