ntMaximum amount of Barium sulphate in terms of moles precipitated on mixing equal volumes 1 litre each of Barium Chloride(0.5M) with sulfuric acid(1M) will correspond to-n nt1) 0.5molesn nt2) 1.0n nt3) 1.5n nt4) 2.0molesn

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Which of the following precipitate is formed on mixing sodium sulphate with barium chloride solution

A) black precipitate of Barium sulphate

B) white precipitate of Barium sulphate

C) red precipitate of Barium sulphate

D) blue precipitate of Barium sulphate

Q. The maximum amount of

{B a S O}_{4}

(in terms of moles) precipitated on mixing equal volume one liter each of

{B a C l}_{2}

(0.5 M)

with

H_{2} {S O}_{4}

(1 M)

will correspond to:

Q. What is the maximum amount of

B a {S O}_{4}

in terms of moles precipitated on mixing equal volumes

1

liter each of

B a {C l}_{2}

2.05 M

with

H_{2} {S O}_{4}

1 M

Barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate.

Translate and balance

When equal volumes of $2 \times 10^{- 6} M$ $B a C l_{2}$ solution and $2 \times 10^{- 5} M$ $N a_{2} S O_{4}$ solution are mixed - $B a S O_{4}$ is precipitated out - True or False?

The solubility product of barium sulphate is $1 \times 10^{- 10}$ .

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