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ntRange of f(x) =cos (ksinx) is [-1, 1] then least positive integral value of k isn

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Q. Range of function

f (x) = cos (k sin x)

is [-1 , 1 ] then the least positive integral value of k will be

Q. Range of function f(x) = cos(ksinx) is [ -1,1], then the least positive integral value of k will be?

{(\frac{1 + i}{1 - i})}^{m} = 1

, then the least positive integral value of m is

{(\frac{1 + i}{1 - i})}^{m} = 1

, then find the least positive integral value of m.

If ${[\frac{1 + i}{1 - i}]}^{m} = 1$ , then find the least positive integral value of m.

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