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Mixed Combination of Cells

ntterminal po...

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ntterminal potential difference(V) of a cell(emf E and internal resistance r) is measured as a function of current(I) flowing through it. The slope and intercept of graph between Vand I then respectively are equal to -r and E how?n

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Q. A student measures the terminal potential difference

(V)

of a cell (of emf

ε

and internal resistance

r

) as a function of the current

(I)

flowing through it. The slope and intercept of the graph between

V

I

are respectively equal to

Q. For a cell, a graph is plotted between the potential difference

V

across the terminals of the cell and the current

I

drawn from the cell (figure). The emf and the internal resistance of the cell are

E

r

respectively. Then

Q. A battery of emf

E

and internal resistance

r

is connected across a resistance

R

R

can be adjusted to any value greater than or equal to zero. A graph is plotted between the current

(i)

passing through the resistance and potential difference

(V)

across it. Select the correct alternative(s).

Q. The values of current (I) flowing through a given resistor of resistance (R), for the corresponding values of potential difference (V) across the resistor are given below :

\begin{matrix} V (volts) & 0.5 & 1.0 & 1.5 & 2.0 & 2.5 & 3.0 & 4.0 & 5.0 I (amperes) & 0.1 & 0.2 & 0.3 & 0.4 & 0.5 & 0.6 & 0.8 & 1.0 \end{matrix}

Plot a graph between current (I) and potential difference (V) and determine the resistance (R) of the resistor.

Q. The emf of a cell is

ε

and its internal resistance is

r

. Its terminals are connected to a resistance

R

. The potential difference between the terminals is

1.6 V

R = 4 Ω

, and 1.8 V for

R = 9 Ω

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