Question

Nucleus radius of ${}_6{C}^{12}$ is $3\times {10}^{-15}$ metre. What is density ratio of $d_C/d_{H_{2}O}$?

• A. $1.76\times {10}^{17}$
• B. $1.76\times {10}^{14}$
• C. $1.76\times {10}^7$
• D. $17.6\times {10}^{17}$

Answer 1

Answer: (B)

$1.76\times {10}^{14}$

Density $=M/V=M/\left(\right(4/3\left)\pi r^3\right)$ where r is $3\times {10}^{-15}$ and M is $12\times 1.66c\times {10}^{-24}g$
So density ratio is $1.76\times {10}^{14}$ (water density is 1 gm/ml)