Question

Number of $2$-digit numbers (having different digits), which are divisible by $5$ is

• A. $8$
• B. $9$
• C. $17$
• D. $72$

Answer 1

The correct option is C $17$

For any number to be divisible by $5$ the units digit should be either $0$ or $5$
Now $\left(i\right)$ If the units digit is $5$ then total possible numbers are $8$ (as $0$ can't be on tens place for a $2$ digit number)
$\left(ii\right)$If the units digit is $0$ then possible numbers are $9$
$\therefore$using addition principle, total possible numbers are $8+9=17$