Question

Number of $4$ cm cubes that could be placed into the box.

• A. $48$
• B. $45$
• C. $42$
• D. $40$

Answer 1

The correct option is A $48$

$\therefore$ volume of internal dimension $=(27-3)(19-3)(11-3)=3072$
Volume of cube$=4^3=64$

No. of cubes $=\frac{internalvolume}{volumeofcube}$

$=\frac{3072}{4\times 4\times 4}$

$=48$