The correct option is B 52
For any number to be divisible by 6 the number should be even and divisible by 3.
Now, for number to be even the last digit should be 0,2,4.
Now, if the last digit is 0 then first 3 digits can be (1,2,3) or (2,3,4) or (3,4,5) or (1,3,5).
So, possible numbers are =4×3!=24
Now, if the last digit is 2 then first 3 digits can be (0,1,3) or (0,3,4) or (1,4,5).
So, possible numbers are =4+4+3!=14
Now, if the last digit is 4 then first 3 digits can be (0,2,3) or (0,3,5) or (1,2,5).
So, possible numbers are =4+4+3!=14
Hence, total numbers are 14+14+24=52