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Byju's Answer
Standard XII
Mathematics
Combination
Number of 5...
Question
Number of
5
digited numbers using
0
,
1
,
2
,
3
,
4
,
5
divisible by
5
repetition is allowed
A
216
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B
100
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C
140
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D
180
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Solution
The correct option is
A
216
we have,
0
,
1
,
2
,
3
,
4
,
5
¯
¯
¯
↓
4
C
1
¯
¯
¯
↓
4
C
1
¯
¯
¯
↓
3
C
1
¯
¯
¯
↓
2
C
1
¯
¯
¯
↓
1
C
1
=
5
×
4
×
3
×
2
×
1
=
120
when unit digit 5
¯
¯
¯
↓
5
C
1
¯
¯
¯
↓
4
C
1
¯
¯
¯
↓
3
C
1
¯
¯
¯
↓
2
C
1
¯
¯
¯
↓
1
C
1
=
4
c
1
×
4
c
1
×
3
c
1
×
2
c
1
×
1
=
96
Total 5 digit No=
=
120
+
96
=
216
Hence this is the answer
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