wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Number of 5 digited numbers using 0,1,2,3,4,5 divisible by 5 repetition is allowed

A
216
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
140
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
180
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 216
we have,
0,1,2,3,4,5

¯¯¯4C1¯¯¯4C1¯¯¯3C1¯¯¯2C1¯¯¯1C1

=5×4×3×2×1

=120

when unit digit 5
¯¯¯5C1¯¯¯4C1¯¯¯3C1¯¯¯2C1¯¯¯1C1

=4c1×4c1×3c1×2c1×1

=96

Total 5 digit No=
=120+96

=216

Hence this is the answer


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Combinations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon