Number of acyclic isomers represented by molecular formula $C_{4} H_{10} O$ are:

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Solution

The correct option is A
7

$C_{4} H_{10} O$

$\Rightarrow C H_{3} C H_{2} C H_{2} C H_{2} O H$

$C H_{3} - C H_{2} - C H | O H - C H_{3}$

$C H_{3} - C H_{3} | C H - C H_{2} - O H$

$C H_{3} - C H_{3} | C | C H_{3} - O H$

$C H_{3} - O - C H_{2} - C H_{2} - C H_{3}$

$C H_{3} - C H_{2} - O - C H_{2} - C H_{3}$

$C H_{3} - C H | C H_{3} - O - C H_{3}$

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