Number of all five digit numbers of the form “34a5b”(where a, b are digits) divisible by 36, is___
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Solution
x = 34a5b is divisible by 36 ⇒34a 5b is divisible by 4 and 9. Divisible by 4 : 5b is divisible by 4 ⇒b=2,6 If b = 2 : 3 + 4 + a + 5 + 2 = 14 + a; x is divisible by 9 ⇒ a = 4 b = 6 : 3 + 4 + a + 5 + 6 = 18 + a x is divisible 9 ⇒ a = 0,9