wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Number of all four digit numbers having different formed of the digits 1, 2, 3, 4 and 5 and divisible by 4 is


A

24

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

30

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

125

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

24


In order to make number divisible by 4, its last two digits must be divisible by 4, which in this case can be 12, 24. 32 or 52.

Since repetition of digits is not allowed, the remaining first two digits can be arranged in 3×2 ways in each case.

Total number of numbers that can be formed 4×3×2 = 24


flag
Suggest Corrections
thumbs-up
18
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Counting Principle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon