Number of atoms in $12 g$ of $_{6}^{12} C$ is:

6

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12

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6.022 \times 10^{23}

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12 \times 6.022 \times 10^{23}

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Solution

The correct option is C $6.022 \times 10^{23}$
First, we'll have to calculate the number of moles.
Number of moles = $\frac{Given weight}{Molecular Weight}$
$= \frac{12}{12} = 1 m o l e$
1 mole of $_{6}^{12} C$ has an atomic mass of 12g.
And by Avagadro's rule, one mole of the compound contains $6.0223 \times 10^{23}$ atoms.
$\Rightarrow$ 12g of $_{6}^{12} C$ contains $6.0223 \times 10^{23} a t o m s$ (Avagadro number of atoms).

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Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
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(c) Which weighs more,

6.022 \times 10^{23}

molecules of

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6.022 \times 10^{23}

molecules of

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One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

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One mole of oxygen gas at STP is equal to...........

(a) $6.022 \times 10^{23}$ molecules of oxygen

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(d) 32 g of oxygen

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Number of atoms in 12g of 126C is:

Number of atoms in $12 g$ of $_{6}^{12} C$ is: