Number of bonding electrons and anti-bonding electrons in $2 p$ MO of $N_{2}$ molecule are respectively:

6, 2

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4, 0

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6, 0

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4, 2

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Solution

The correct option is C $6, 0$
From the diagram, we can see that there are 6 bonding electrons in $2 p M O$ of nitrogen and no antibonding electron.

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